00:01
All right, so here using spherical coordinates, where we know x here is going to be a 2 sine of phi, cosine of theta, and y is equal to 2 sine of phi, sine of theta, and z is equal to 2 .0 and 2.
00:21
Cosine fee, where fee is between zero and pi over two for the upper hemisphere and theta is between zero and two pi.
00:30
So our function, four z squared is our g of x, y, z is going to be equal to four times two cosine of f, all squared, is going to be equal to 16 cosine, cosine squared fee.
00:46
And then the surface element in four -coordinates our ds is going to be four side of fee d -theta.
00:56
So then we have our surface integral, and we have for the theta integral, it's going to be the integral from 0 to 2 -5 of this d -theta, which is equal to 2 -5.
01:07
And then for the fee integral, we have the integral from 0 to pi over 2 of cosine squared fee.
01:16
Sine of fee.
01:21
And we can use a substitution here, letting u be equal to cosine of fee...