00:04
The intensity of the transmitted light from an unpolarized source when it passes through a polarizer is given by mallot's law i is equals to i0 into cos square theta where i is the intensity of light i0 is initial intensity of light theta is the angle between the polarization position axis of polarizer and the direction of incident light.
02:01
When unpolarized light passes through an ideal polarizing filter its intensity is reduced by half.
02:40
So, the angle between the incident light and polarization axis is 0 degree.
03:04
Therefore, i1 is equals to 1 by 2 into i0 cos square theta which is equals to 1 by 2 into i0 into cos square 0 degree which is equals to 1 by 2 into i0 into 1.
03:25
Therefore, i1 is equals to 1 by 2 i0.
03:31
Now, the emerging light with intensity i1 strikes the second polarizer whose axis is at 62 degree to that the first the angle between the polarization axis of the second polarizer and the direction of emerging light is 62 degree.
04:55
Therefore, using mallot's law again i2 is equals to i1 cos square theta which is equals to i1 cos square 62 degree.
05:17
Therefore, substituting i1 is equals to i0 i2 is equals to 1 by 2 into i0 into cos square 62 degree which is equals to 1 by 2 into i0 into cos square 62 degree.
05:46
Therefore, i1 is equals to i0 cos square 62 degree.
05:48
Therefore, i1 is equals to i0 cos square 62 degree...