00:01
All right, we have g of x and h of x, and then f of x is the composition of g and h, and then we want to find f inverse.
00:13
Okay, so i think, because it says find it directly, so i think it wants us to first find f of x, which is g of x cubed.
00:25
So that would be 2x cubed plus 3.
00:30
So that's y.
00:31
So then switch the x and y and solve for y so the cube root of x minus 3 over 2 equals y which is f inverse okay now um g inverse of x it was 2x plus 3 so it would be x minus 3 over 2 and h inverse of x would be the cube root of x uh cube root so you can see that f inverse of x is the cube root of x minus three over two so it's h inverse of g inverse of x.
01:43
All right.
01:47
So now in the second one, f of x is g of the square root of x.
01:55
And so that would be the square root of x squared plus 1, which would be x plus 1.
02:03
So y equals x plus 1.
02:06
X equals y plus 1.
02:08
So y is x minus 1, which is f inverse here.
02:18
Okay now, what about up here? g inverse of x.
02:23
Oh, we can't find g inverse of x because this is not one to one to one.
02:28
Oh wait, do we know that x is? okay, well, g inverse does.
02:37
Doesn't exist because g of x is not one to one...