inversion method. \begin{tabular}{r|r} \hline \( 3 x_{1}-5 x_{2} \) & \( =1 \) \\ \( -2 x_{1}+x_{2} \) & \( =-3 \) \\ \hline \end{tabular}
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The given system of equations can be written in matrix form as follows: \[ \begin{bmatrix} 3 & -5 \\ -2 & 1 \end{bmatrix} \begin{bmatrix} x_{1} \\ x_{2} \end{bmatrix} = \begin{bmatrix} 1 \\ -3 \end{bmatrix} \] We denote the coefficient matrix by A, the Show more…
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