Independent random samples selected from two normal populations produced the sample means and standard deviations shown to the right. a. Assuming equal variances, conduct the test $H_0: (mu_1 - mu_2) = 0$ against $H_a: (mu_1 - mu_2) eq 0$ using $alpha = 0.05$. b. Find and interpret the 95% confidence interval for $(mu_1 - mu_2)$. Sample 1 Sample 2 $n_1 = 17$ $n_2 = 9$ $ar{x}_1 = 5.2$ $ar{x}_2 = 7.5$ $s_1 = 3.9$ $s_2 = 4.7$
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Step 1: State the null and alternative hypotheses - Null hypothesis (Ho): The means of the two populations are equal (μ1 = μ2) - Alternative hypothesis (Ha): The means of the two populations are not equal (μ1 ≠ μ2) Show more…
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Independent random samples selected from two normal populations produced the sample means and standard deviations shown in the table below. Assuming equal variances, conduct the test H0: (μ1 - μ2) = 0 against Ha: (μ1 - μ2) ≠ 0 at a significance level of α = 0.05. Find and interpret the 95% confidence interval for (μ1 - μ2).
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Conduct a hypothesis test for H0: μ = 0.5 versus Ha: μ ≠ 0.5 using α = 0.05. Assuming the population is normally distributed with standard deviation σ = 1.2 and the mean of 40 samples yields: ȳ = 0.7.
Researcher wanted to make some statistical inferences about the difference between the mean waiting time clinic (̄μ₁) and the mean waiting time clinic "8" (̄μ₂). To do so, he selected a random sample of 35 patients from clinic and found that the sample mean was 44.23 minutes. Also, he independently selected a random sample of 35 patients from clinic and found that the sample mean was 25 minutes. Assumed that the populations are normal with variances for clinic time. For testing (Ho: ̄μ₁ = ̄μ₂) against (HA: ̄μ₁ ≠ ̄μ₂), the value of the test statistic Z = -2.82. The chosen significance level is 0.01 (α=0.01).
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