Question

is thrown upward with an initial velocity of 128 ft/sec from a height of 560 ft. ight h, in feet, after t seconds is given by $h = -16t^2 + 128t + 560$. After how long will it take for the ball ach to its maximum height? (Round your answer to 1 decimal place.) The ball will

          is thrown upward with an initial velocity of 128 ft/sec from a height of 560 ft.
ight h, in feet, after t seconds is given by
$h = -16t^2 + 128t + 560$. After how long will it take for the ball
ach to its maximum height? (Round your answer to 1 decimal place.) The ball will

is thrown upward with an initial velocity of 128 ft/sec from a height of 560 ft.
ight h, in feet, after t seconds is given by
h = -16t^2 + 128t + 560. After how long will it take for the ball
ach to its maximum height? (Round your answer to 1 decimal place.) The ball will

Added by Anne F.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Supreeta N

12/10/2023

Step 1

To find the maximum height, we need to find the vertex of the parabola represented by this equation. Show more…

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is thrown upward with an initial velocity of 128f(t)/(sec) from a height of 560ft. ight h, in feet, after t seconds is given by =-16t^(2)+128t+560. After how long will it take for the ball ach to its maximum height? (Round your answer to 1 decimal place.) The ball will is thrown upward with an initial velocity of 128 ft/sec from a height of 560 ft ght h,in feet,after t seconds is given by ch to its maximum height?(Round your answer to 1 decimal place.)The ball will