It was reported that in a survey of 4749 American youngsters aged 6 to 19, 18% were seriously overweight (a body mass index of at least 30; this index is a measure of weight relative to height). Calculate a confidence interval using a 99% confidence level for the proportion of all American youngsters who are seriously overweight. (Round your answers to three decimal places.) Interpret the resulting interval. We are 99% confident that the true proportion of American youngsters who are seriously overweight is above this interval. We are 99% confident that the true proportion of American youngsters who are seriously overweight is within this interval. We are 99% confident that the true proportion of American youngsters who are seriously overweight is outside this interval. We are 99% confident that the true proportion of American youngsters who are seriously overweight is below this interval.
Added by Andr-S T.
Step 1
First, we need to find the sample proportion (p̂) of seriously overweight youngsters. Since 18% of 4749 youngsters are seriously overweight, we can calculate p̂ as follows: p̂ = (18% of 4749) / 4749 p̂ = (0.18 * 4749) / 4749 p̂ = 855 / 4749 p̂ ≈ 0.180 Show more…
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