00:01
For this question, the molar mass of dexutrize is the sum of atomic masses and elements present.
00:08
The atomic mass is equal to c is equal to 12, h is equal to 1, and o is equal to 16.
00:20
Therefore, computing the molar mass, that is equal to 180 gram per mole.
00:34
Okay.
00:35
So the molarity is grams of so.
00:36
Solute per liter of solution the solution can contain 5 gram of dextros in 100 m l of solution so as we know 1 liter is equal to 1 ,000 ml of solution and the 1 ,000 ml would contain 1 ,000 into 5 divided by 100 so 1 liter would contain 50 gram of dextrose okay now the modes of dextros is mass divided by molar mass is equal to 0 .28 moles.
01:18
Now 0 .28 moles of dextros is present in a 1 litre of solution.
01:23
So, molarity of dextrose is equal to 0 .28 moles per liter.
01:45
Now coming to the second part, 100ml of solution contains 5gm of 5 grams of dextr...