If $x^3 + 8x^2 + mx - 5$ is divided by $x + 1$ and the remainder is $n$, express $m$ in terms of $n$.
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From the right side, the coefficient of * is #, and the coefficient of 1 is # + m. Setting up the equations: Ix' + 8r2 = # Ku 5 = # + m Now, we can solve the first equation for #: # = Ix' + 8r2 Substituting this value of # into the second equation: Ku 5 = Show more…
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