When 10x^3 + mx^2 - x + 10 is divided by 5x - 3, the quotient is 2x^2 + nx - 2 and the remainder is 4. Solve for the values of m and n.
Added by Steven R.
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Given that the polynomial $10x^3 + mx^2 + x + 10$ is divided by $5x$, we have the following equation: $10x^3 + mx^2 + x + 10 = (5x)(2x^2 + nx) + 4$ Expanding the right side, we get: $10x^3 + mx^2 + x + 10 = 10x^3 + 5nx^2 + 4$ Show more…
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