00:01
When the following equation is balanced properly under basic conditions, what are the coefficients of species shown? so water appears in the balance equation as fill in the blanks, right? reactant product neither with a coefficient of i enter zero for neither which element is oxidized.
00:22
This is what it is asked.
00:23
So remember to balance the equation under basic conditions, we start by balancing the oxygen atom.
01:07
We start by balancing the oxygen atoms by adding h2o molecules, right? so we will write a balance equation here.
01:38
Next we will balance.
01:40
This is first step, right? and second step is next we balance hydrogen, hydrogen atoms, right? so this is this is first step, right? for first part of this problem, this is second part.
02:13
So this is first step.
02:15
Now second step would be after balancing after adding h plus ion, right? for balancing h plus ion, we need to add it h plus ion.
02:31
So it would be giving us mno2 plus clo3 minus plus h2o that gives us cl negative plus mno4 minus plus h2o.
02:47
Now here second equation would second option would be the same, right? we need to add, we start balancing the like the metals first, right? and balance the oxygen atoms by adding h2o molecules, right? same procedure is followed.
03:18
And after that we will add h plus ions, right? so it will give us cadmium 2 plus plus nickel 2 plus plus 2h plus that gives us cd cadmium plus nio2 plus h2o.
03:42
This will be the equation.
03:48
Now final balanced equation would be final balanced equation would be what it would be cd plus...