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stefanie martinez

stefanie m.

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Question 4 UPLOAD A COPY(PICTURE) OF YOUR COMPLETE SOLUTION WITH THE BOXED ANSWER. 20 Points Hexane (0.710 g) was burned in a bomb calorimeter containing 935 g of water. T increased from 22.15°C to 29.12°C. Calculate the heat evolved per mole of hexane burned. $C_{cal} = 895 J°C^{-1}$. (10pts) Use the editor to format your answer $C_6H_{14}(g) + O_2 \to CO_2 + H_2O(l)$

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Jump to level 1 An unbalanced chemical reaction is: 1KCl + _O2 → _KCIO3 The modified stoichiometric coefficients are: O2: Ex: 5 KCIO3: Ex: 4

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Question 24 Microorganisms used in fermentation are heterotrophs due to: Use of inorganic compounds for energy Use of carbon dioxide for energy Use of organic compounds for energy Use of light for energy 2 pts

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How is water and caffeine chemically digested and absorbed in the digestive system?

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Consider the equation $y = 300 - 12x$. What is the y-intercept?

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the spinner was spun 36th mes it landed on A 17 times , on B 11 times and on C 8 times. compute the probability that the spinner will land on B on the next spin

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Three springs and a mass are attached to a rigid, weightless bar PQ as shown in Fig. Find the natural frequency of vibration of the system.

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(a) A Communal Aerial Broadcasting Distribution (CABD) System is established for a small domestic house as shown in Figure 3a. Socket 2 Pre Amplifier 15m Socket 1 28m 10m 32m Splitter Splitter Socket 8 40m Socket 3 5m Tee 22m Socket 4 8m 10m 16m Tee Tee 18m 5m 5m Socket Socket Socket 5 6 7 Figure 3a Given that: Signal level at the aerial = 55 dB?V Aerial gain = 16 dB 2-way Splitter loss = 4 dB Tee through loss = 5.5 dB TV socket loss = 1 dB Pre-Amplifier gain = 22 dB Tee side loss = 10 dB 4-way Splitter loss = 7 dB Coaxial cable loss = 23 dB/100m i) Determine the signal levels for each of the socket outlet; (8 marks) ii) Check the sockets in part (i) and identify any possible problems that (3 marks) may happen in the reception of digital terrestrial television (DTT).

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Problem: Patm z d L Name: $\left(\frac{P_1}{\rho} + \frac{v_1^2}{2} + gz_1\right) - \left(\frac{P_2}{\rho} + \frac{v_2^2}{2} + gz_2\right) = h_{Ltot}$ $h_{Ltot} = h_f + h_{Lm}$ $h_f = f \frac{Lv^2}{D2}$ $h_{Lm} = K \frac{v^2}{2}$ $Re = \frac{\rho vD}{\mu}$ Patm Water flows at 0.03 m³/s through a 75 mm diameter pipe, with L = 100 m, attached to a constant level reservoir. Inlet loss coefficient, K = 0.5, p = 999 kg/m³, µ = 1 E-3 kg/m-s. Find: the reservoir depth to maintain the flow.

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Use Thévenin's theorem to find $V_o$ in the circuit in the figure below. Break the network just to the right of the vertical 2k Ohm resistor containing $I_x$.

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