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Question 4 UPLOAD A COPY(PICTURE) OF YOUR COMPLETE SOLUTION WITH THE BOXED ANSWER. 20 Points Hexane (0.710 g) was burned in a bomb calorimeter containing 935 g of water. T increased from 22.15°C to 29.12°C. Calculate the heat evolved per mole of hexane burned. $C_{cal} = 895 J°C^{-1}$. (10pts) Use the editor to format your answer $C_6H_{14}(g) + O_2 \to CO_2 + H_2O(l)$

Name: question 4 upload a copypicture of your complete solution with the boxed answer 20 points hexane 0710 g was burned in a bomb calorimeter containing 935 g of water t increased from 2215c to 2 22383
Uploaded: 2022-04-10T10:15:19-08:00
Duration: 2 min 45 s
Channel: Sri K
Description: question 4 upload a copypicture of your complete solution with the boxed answer 20 points hexane 0710 g was burned in a bomb calorimeter containing 935 g of water t increased from 2215c to 2 22383

          Question 4
UPLOAD A COPY(PICTURE) OF YOUR COMPLETE SOLUTION WITH THE BOXED ANSWER.
20 Points
Hexane (0.710 g) was burned in a bomb calorimeter containing 935 g of water. T increased from
22.15°C to 29.12°C. Calculate the heat evolved per mole of hexane burned. $C_{cal} = 895 J°C^{-1}$.
(10pts)
Use the editor to format your answer
$C_6H_{14}(g) + O_2 \to CO_2 + H_2O(l)$

question 4 upload a copypicture of your complete solution with the boxed answer 20 points hexane 0710 g was burned in a bomb calorimeter containing 935 g of water t increased from 2215c to 2 22383

Added by Stefanie M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

04/10/2022

Step 1

12°C - 22.15°C = 6.97°C$ Show more…

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Question 4 UPLOAD A COPY(PICTURE) OF YOUR COMPLETE SOLUTION WITH THE BOXED ANSWER. 20 Points Hexane (0.710 g) was burned in a bomb calorimeter containing 935 g of water. T increased from 22.15°C to 29.12°C. Calculate the heat evolved per mole of hexane burned. $C_{cal} = 895 J°C^{-1}$. (10pts) Use the editor to format your answer $C_6H_{14}(g) + O_2 \to CO_2 + H_2O(l)$