For the point P(12, -6) and Q(19, -1), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
Added by Jesse D.
Close
Step 1
To find the distance between two points in a coordinate plane, we can use the distance formula: d(P,Q) = √((x2 - x1)^2 + (y2 - y1)^2) In this case, x1 = 12, y1 = -6, x2 = 19, and y2 = -1. Plugging in the values, we get: d(P,Q) = √((19 - 12)^2 + (-1 - Show more…
Show all steps
Your feedback will help us improve your experience
Yujie Wang and 82 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
For the points $P$ and $Q .$ find $(a)$ the distance $d(P, Q)$ and $(b)$ the coordinates of the midpoint $M$ of line segment $P Q$. $$ P(-5,-6), Q(7,-1) $$
Graphs and Functions
Rectangular Coordinates and Graphs
For the points $P$ and $Q .$ find $(a)$ the distance $d(P, Q)$ and $(b)$ the coordinates of the midpoint $M$ of line segment $P Q$. $$ P(6,-2), Q(4,6) $$
For the points $P$ and $Q .$ find $(a)$ the distance $d(P, Q)$ and $(b)$ the coordinates of the midpoint $M$ of line segment $P Q$. $$ P(-6,-5), Q(6,10) $$
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD