Use the Taylor polynomial of degree 4 at x = 0 given below to approximate the quantity $\sqrt[4]{1.12}$. $P_4(\sqrt[4]{1+x}) = 1 + \frac{1}{4}x - \frac{3}{32}x^2 + \frac{7}{128}x^3 - \frac{77}{2048}x^4$ $\sqrt[4]{1.12} \approx$ (Round to four decimal places as needed.)
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The Taylor polynomial of degree 4 at x=0 is given by: P(x) = f(0) + f'(0)x + (f''(0)/2!)x^2 + (f'''(0)/3!)x^3 + (f''''(0)/4!)x^4 Show more…
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