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8. [-/2 Points] DETAILS MY NOTES LARCALC11 3.1.031. ASK YOUR TEACHER Find the absolute extrema of the function on the closed interval. $g(x) = \frac{3x^2}{x - 6}$, $[-3, 2]$ minimum $(x, y) = ( )$ (smaller x-value) minimum $(x, y) = ( )$ (larger x-value) maximum $(x, y) = ( )$ Submit Answer

          8. [-/2 Points]
DETAILS
MY NOTES
LARCALC11 3.1.031.
ASK YOUR TEACHER
Find the absolute extrema of the function on the closed interval.
$g(x) = \frac{3x^2}{x - 6}$, $[-3, 2]$
minimum $(x, y) = (		)$ (smaller x-value)
minimum $(x, y) = (		)$ (larger x-value)
maximum $(x, y) = (		)$
Submit Answer

8. [-/2 Points]
DETAILS
MY NOTES
LARCALC11 3.1.031.
ASK YOUR TEACHER
Find the absolute extrema of the function on the closed interval.
g(x) = (3x^2)/(x - 6), [-3, 2]
minimum (x, y) = ( ) (smaller x-value)
minimum (x, y) = ( ) (larger x-value)
maximum (x, y) = ( )
Submit Answer

Added by Gregory G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/14/2023

Step 1

To find the critical points, we need to find where the derivative of g(x) is equal to zero or undefined. g(x) = (3x^2)/(x-6) g'(x) = (6x(x-6) - 3x^2) / (x-6)^2 Setting g'(x) = 0, we get: (6x(x-6) - 3x^2) = 0 6x^2 - 36x - 3x^2 = 0 3x^2 - 36x = 0 3x(x - 12) = 0 x = Show more…

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LARCALC11 3.1.031. Find the absolute extrema of the function on the closed interval. g(x) = (3x^2)/(x-6), [-3,2] minimum (x,y) = (,) (smaller x-value) minimum (x,y) = (◻) (larger x-value) maximum (x,y) = (,) 8.[-/2 Points] DETAILS MY NOTES LARCALC113.1.031. ASKYOURTEACHER Find the absolute extrema of the function on the closed interval 9(x) = √3x^2 [-3,2] minimum (x, y) (smaller x-value) minimum (x,y) (larger x-value) maximum (x,y) Submit Answer