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REMARKS Measuring such a vibration is a good way of determining the local value of the acceleration of gravity.
QUESTION Does a simple pendulum of length 0.50 m have a larger or smaller frequency of vibration than a simple pendulum of length 1.0 m? Explain. (Select all that apply.)
Smaller. A longer pendulum has a longer period and smaller frequency according to Ļ = ā(mg/(mL)) = ā(g/L).
Smaller. A longer string makes the restoring force smaller for each pendulum angle.
Larger. It increases the distance the pendulum bob rises as it swings through the same angle, doubling its frequency.
Larger. It increases the distance the pendulum bob must move along its path, making it move faster.
There is no change. The frequency of a pendulum does not depend on its amplitude.
Examine the derivation of the frequency of a pendulum. Consider whether the restoring force Ft is increased or decreased by making the string longer. Does the lack of dependence on amplitude imply a lack of dependence on length?
PRACTICE IT
Use the worked example above to help you solve this problem. Using a small pendulum of length 0.178 m, a geophysicist counts 73.0 complete swings in a time of 60.0 s. What is the value of g in this location?
10.97
Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. m/s²