00:01
So, we are given that y is equal to x and y is equal to x square are the bounded regions.
00:16
So by revolving them, we just have to express the volume of solid generated if in the first a part, the first about the x axis and the second about the y axis by using in the a part as according to cell method.
00:39
So, let it started with the solution.
00:43
So, first of all we are writing it down for the cell method that means by using that cell method, the volume generated can be given as let's say v is equal to integral a to b to x y into the bracket y t of y minus f of y dy.
01:14
So, let's plug in the required values.
01:18
So, if you say the value of y.
01:20
So, x is equal to y, but here x should become equal to under root of y which representing g of y and this representing the f of y.
01:31
Substituting this here, so integral will go from the initial limit will be 0 and the final limit will be 1 and here it should be a 2 x y into the bracket under root of y minus of y dy.
01:46
And hence, therefore, the required volume generated v should be equals to 0 to 1 2 x y into the bracket under root of y minus of y dy.
02:00
So, this is the answer for one of the part of a.
02:07
Similarly, in the same a part, we have to state the volume about y axis.
02:14
For that, we can directly write down it as integral of 0 to 1 2 x y into the bracket g of x minus f of x.
02:28
So, this we can write down as v is equals to by shell method integral a to b 2 x y into the bracket g of x minus f of x dx.
02:44
So, let's plug in the values...