Question

\[ \left\{\begin{array}{c} f_{1 x}^{\prime} \\ f_{3 x}^{\prime} \end{array}\right\}=(31,500)\left[\begin{array}{rr} 1 & -1 \\ -1 & 1 \end{array}\right]\left[\begin{array}{llll} 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1 \end{array}\right]\left\{\begin{array}{l} u_{1}=-0.05 \\ v_{1}=0.0337 \\ u_{3}=0 \\ v_{3}=0 \end{array}\right\}^{\prime} \] Performing the matrix triple product in Eq. (3.6.18), we obtain \[ f_{1 x}^{\prime}=1061 \mathrm{kN} \quad f_{3 x}^{\prime}=-1061 \mathrm{kN} \] Verification of the computations by checking that equilibrium is satisfied at node 1 is left to your discretion.

          \[
\left\{\begin{array}{c}
f_{1 x}^{\prime} \\
f_{3 x}^{\prime}
\end{array}\right\}=(31,500)\left[\begin{array}{rr}
1 & -1 \\
-1 & 1
\end{array}\right]\left[\begin{array}{llll}
0 & 1 & 0 & 0 \\
0 & 0 & 0 & 1
\end{array}\right]\left\{\begin{array}{l}
u_{1}=-0.05 \\
v_{1}=0.0337 \\
u_{3}=0 \\
v_{3}=0
\end{array}\right\}^{\prime}
\]

Performing the matrix triple product in Eq. (3.6.18), we obtain
\[
f_{1 x}^{\prime}=1061 \mathrm{kN} \quad f_{3 x}^{\prime}=-1061 \mathrm{kN}
\]

Verification of the computations by checking that equilibrium is satisfied at node 1 is left to your discretion.

${ f1 x^' f3 x^' }=(31,500)[ 1 -1 -1 1 ][ 0 1 0 0 0 0 0 1 ]{ u1=-0.05 v1=0.0337 u3=0 v3=0 }^' Performing the matrix triple product in Eq. (3.6.18), we obtain f1 x^'=1061 kN f3 x^'=-1061 kN Verification of the computations by checking that equilibrium is satisfied at node 1 is left to your discretion.$

Added by Charles H.

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