00:01
Here in this question, the mean mu is given as 266 and sigma is given as 16.
00:07
The first thing is we need to find p of x less than 240.
00:12
So, which is p of x minus mu by sigma less than 240 minus 266 divided by 16, which is p of z less than minus 1 .63.
00:26
So, 0 .0516 is the required probability.
00:31
The second one is p of 240 less than x less than 270.
00:37
So, which is p of 240 minus 266 by 16 less than z less than 270 minus 266 divided by 16.
00:52
So, which is p of minus 1 .63 less than z less than 0 .25, which is equal to p of z less than 0 .25 minus p of z less than minus 1 .63, which is equal to 0 .5987 minus 0 .0516.
01:12
So, the required probability is 0 .5471...