00:01
So, in this question, we are given the function fx which is equals to negative.
00:07
Inside the bracket we have 3x plus of 3 sin x where 0 is lying in between x less than equals to 2pi.
00:20
So we need to find the critical point for the given function fx.
00:25
So, for the critical point we know the function fx means the derivative of the function f dash is equals to 0 or it is undefined.
00:38
So if we find out f dash x from here, we will be getting minus of 3 and then i will be getting minus of 3 cos x.
00:46
So for the critical point we equate this to 0.
00:49
So when we equate it to 0, then i will get, sorry this is negative 3 over this side.
00:57
So this is negative 3, negative 3 cos of x is equals to 0.
01:02
So 3 cos x is equal to negative 3.
01:05
So now you can cancel 3 from both the sides, you will get cos of x is equal to minus 1...