Question

Let \begin{bmatrix} 3\\13\\-4\\-3 \end{bmatrix}, \vec{v} = \begin{bmatrix} -1\\-4\\-3\\3 \end{bmatrix}, and let $W$ the subspace of $\mathbb{R}^4$ spanned by $\vec{u}$ and $\vec{v}$. Find a basis of $W^\perp$, the orthogonal complement of $W$ in $\mathbb{R}^4$.

          Let
\begin{bmatrix} 3\\13\\-4\\-3 \end{bmatrix}, \vec{v} = \begin{bmatrix} -1\\-4\\-3\\3 \end{bmatrix},
and let $W$ the subspace of $\mathbb{R}^4$ spanned by $\vec{u}$ and $\vec{v}$. Find a basis of $W^\perp$, the orthogonal complement of $W$ in $\mathbb{R}^4$.
        
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Let

    < b m a t r i x >
, v⃗ = 
    < b m a t r i x >
,
and let W the subspace of ℝ^4 spanned by u⃗ and v⃗. Find a basis of W^⊥, the orthogonal complement of W in ℝ^4.

Added by Lisa M.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Let -17 13 -4 n= ,3= -4 -3 -3 3 and let W the subspace of IR4 spanned by u and . Find a basis of W, the orthogonal complement of W in IR4
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Transcript

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00:03 We're given two vectors u1 in r4, the components 1 -negative 2, 3, 4, and another vector in r4, u2 with components 3 -5 -7 -8.
00:26 And we're asked to find a basis of the subspace w of r4, orthogonal to u1 u2.
00:33 Well, we know that if v lies in this scene where he's like describing something, he's looking inspired with white supremacist.
00:47 We know that if v lies in this basis well let's say z has the form x, y, z, t then z is in w v with u1, any inner product of v with u2 has be equal to 0.
01:20 This implies that x minus 2 y plus 3 z plus 4 2 equals 0 and 3x minus 5 y plus 7 plus 18 equals 0.
01:49 We obtain the system of equations.
01:54 We'll simplify this system.
01:56 You'll subtract 3 of equation 1 from equation 2.
02:01 So they still have equation 1, x minus 2 y, plus 3d, plus 4t, equal 0...
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