Let a > 0 and x1 > 0. Define a sequence (xn) by xn+1 = √ a + xn. Prove that (xn) converges and find its limit.
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Step 1
We prove this by induction. For n = 1, we have x1 > 0 and x2 = √a + x1 > x1, so the statement is true for n = 1. Assume that the statement is true for some n = k, i.e., xk+1 > xk and xk+1 ≤ a + x1. We need to show that the statement is also true for n = k + Show more…
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