00:01
So what we're trying to do is maximize the product.
00:04
Product being a plus one times b plus three.
00:14
Just double checking, i have that.
00:16
Now, what we also have is what i like to call a secondary equation, a problem that, an equation that helps me optimize the situation, that there's a connection between a plus 2b is equal to 53.
00:34
Because right now i have too many unknowns.
00:37
But what i can do is i can solve for a by subtracting that 2b to the right side.
00:43
And now i can take this a value and substitute it with 53 minus 2b.
00:50
And i still have all the other pieces in my product here.
00:55
And what i would do is actually simplify a little bit that we're looking at, 54, minus 2b times b plus 3 and then i would also distribute out so looking at that would be 54 times 3 i like to do that first so i'm distributing everything i don't know if i need to change colors to show you and then you'd have 54b but then you would also have negative 6b so that would be a total of 48b and misspelled there but then you also have to do negative 2b times b, which would be negative 2b squared.
01:39
And now this is where calculus comes into play, where you take the derivative of that.
01:44
And it's just the power rule...
