Let A, B and C be three subsets of a universe U with the following properties: n(A) = 73, n(B) = 75, n(C) = 58, n(A cap B) = 14, n(A cap C) = 31, n(B cap C) = 45 n(A cup B cup C) = 120 Find n(A cap B cap C).
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Plugging in the given values, we have 120 = 73 + 75 + 58 - 14 - 31 - 45 + n(A ∩ B ∩ C). Simplifying, we get 120 = 116 + n(A ∩ B ∩ C). Subtracting 116 from both sides, we have 4 = n(A ∩ B ∩ C). Show more…
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