1. Let $A \triangle B$ be the set of all elements that belongs to either A or B, but not to both A and B. Show that $A \triangle B = (A \setminus B) \cup (B \setminus A)$.
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Step 1: To show that (A)/(_(/))B=((A)/(/)B)\cup ((B)/(/)A), we need to show that an element x belongs to either A or B, but not to both A and B if and only if x belongs to either (A)/(/)B or (B)/(/)A. Show more…
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