Question

Let C be the curve $y = \frac{e^{1.9x} + e^{-1.9x}}{3.8}$, for $0.1 \le x \le 1.7$. A graph containing C follows. Find the surface area of revolution about the x-axis of C. First find and simplify $\sqrt{1 + y'^2} =$ Now find surface area =

Name: let c be the curve y frace19x e 19x38 for 01 le x le 17 a graph containing c follows find the surface area of revolution about the x axis of c first find and simplify sqrt1 y2 now find surfa 70868
Uploaded: 2024-08-30T03:48:44-08:00
Duration: 1 min 31 s
Channel: Zack A
Description: let c be the curve y frace19x e 19x38 for 01 le x le 17 a graph containing c follows find the surface area of revolution about the x axis of c first find and simplify sqrt1 y2 now find surfa 70868

          Let C be the curve $y = \frac{e^{1.9x} + e^{-1.9x}}{3.8}$, for $0.1 \le x \le 1.7$. A graph containing C follows.
Find the surface area of revolution about the x-axis of C.
First find and simplify $\sqrt{1 + y'^2} =$
Now find surface area =

$let c be the curve y frace19x e 19x38 for 01 le x le 17 a graph containing c follows find the surface area of revolution about the x axis of c first find and simplify sqrt1 y2 now find surfa 70868$

Added by Purificaci-N P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zack A

08/30/2024

Step 1

$$y = \frac{e^{1.9x} + e^{-1.9x}}{3.8}$$ $$y' = \frac{1}{3.8} (1.9e^{1.9x} - 1.9e^{-1.9x}) = \frac{1.9}{3.8} (e^{1.9x} - e^{-1.9x}) = \frac{1}{2} (e^{1.9x} - e^{-1.9x})$$ Show more…

Show all steps

Thanks for your feedback!

Let C be the curve $y = \frac{e^{1.9x} + e^{-1.9x}}{3.8}$, for $0.1 \le x \le 1.7$. A graph containing C follows. Find the surface area of revolution about the x-axis of C. First find and simplify $\sqrt{1 + y'^2} =$ Now find surface area =