Let f : [a, b] → R be continuous. Let C be the set of all points in [a, b] where f takes the value f(a)+f(b)/2 . Show that C is nonempty and compact.
Added by Tiffany K.
Step 1
Since f is continuous on the closed interval [a, b], by the Extreme Value Theorem, f attains its maximum and minimum values on [a, b]. Let M = f(a) + f(b)/2 and m = f(b) + f(a)/2 be the maximum and minimum values of f on [a, b], respectively. Then, we have: m ≤ Show more…
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