Let f be the function defined by f(x) = -x^2 + 6. What is the average value of f on the interval [-3, -1] written in simplest form?
Added by Shawn V.
Step 1
Step 1: Calculate the average value of f on the interval [-3, -1] using the formula for average value of a function on a closed interval: Average value = (1/(b-a)) * ∫[a to b] f(x) dx Show more…
Show all steps
Close
Your feedback will help us improve your experience
Madhur L and 89 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Let f be the function defined by f( x ) = 1/x . What is the average value of f on the interval [4, 6] ? -1/24 5/24 (1/2) ln (3/2) ln (3/2) (1/2) ln 2
Vishal P.
Find the average value of the function on the given interval. f(x) = ∑x+3; [1, 6] The average value is . (Type an integer or a fraction.)
Find the average value of each function $f$ over the given interval. $$ f(x)=1-x^{2} \text { over }[-1,1] $$
The Integral
Properties of the Definite Integral
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD