Let f left parenthesis x right parenthesis equals 5 x squared plus B x minus 4, where B is a real-valued constant. Which of the following is the slope of the line tangent to f left parenthesis x right parenthesis when x equals 2? 6 plus 2 B 20 plus B 40 plus B 1 minus B B minus 30 41 minus 3 B 76 plus 4 B B minus 10
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Step 1: To find the slope of the line tangent to f(x) at x = 2, we first need to find the derivative of f(x) and then evaluate it at x = 2. Show more…
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a. Find the derivative of $f$ at $x$. That is, find $f^{\prime}(x)$. b. Find the slope of the tangent line to the graph of $f$ at each of the two values of $x$ given to the right of the function. $$f(x)=-5 x+3 ; x=1, x=4$$
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a. Find the slope of the tangent line to the graph of $f$ at the given point. b. Find the slope-intercept equation of the tangent line to the graph of $f$ at the given point. $$f(x)=5 x^{2} \text { at }(-2,20)$$
a. Find the slope of the tangent line to the graph of $f$ at the given point. b. Find the slope-intercept equation of the tangent line to the graph of $f$ at the given point. $$f(x)=2 x^{2}-x+5 \text { at }(0,5)$$
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