Let $f: \mathbb{R}^4 \to \mathbb{R}$ be defined by $f(x) = x^T A x$, where A is a $4 \times 4$ matrix with real entries and $x^T$ denotes the transpose of $x$. The gradient of $f$ at a point $x_0$ necessarily is (a) $2 A x_0$ (b) $A x_0 + A^T x_0$ (c) $2 A^T x_0$ (d) $A x_0$
Added by Irene G.
Close
Step 1
This is a quadratic form where \( x \) is a vector in \(\mathbb{R}^4\) and \( A \) is a \(4 \times 4\) matrix. Show more…
Show all steps
Your feedback will help us improve your experience
Danielle Fairburn and 95 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Danielle F.
Let $\vec{r}=x \vec{i}+y \vec{j}+z \vec{k}$ and $\vec{a}$ be a constant vector. For each of the quantities in (a)-(c), choose the statement in ( $1)-(\mathrm{V})$ that describes it. No reasons are needed. (a) $\operatorname{grad}(\vec{r}+\vec{a})$ (b) $\operatorname{grad}(\vec{r}+\vec{a})$ (c) $\operatorname{grad}(\vec{r} \times \vec{a})$ I Scalar, independent of $\vec{a}$. II Scalar, depends on $\vec{a}$ III Vector, independent of $\vec{a}$. IV Vector, depends on $\vec{a}$. V Not defined.
Differentiating Functions of Several Variables
Gradients and Directional Derivatives in Space
linear question
Willis J.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD