Let f : X → Y be a function and Y be compact Hausdorff. Then f is continuous if and only if the graph of f , G f = {(x, f (x)) : x ∈ X} is closed in X × Y .
Added by Nathan C.
Step 1
Assume f is continuous. Let's show that Gf is closed in X × Y. To do this, we need to show that the complement of Gf in X × Y is open. Let (x, y) be a point in (X × Y) - Gf, which means that y ≠ f(x). Since Y is Hausdorff, there exist disjoint open neighborhoods Show more…
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