Let $f: \mathbb{R} \to \mathbb{R}$ be the function $f(x) = x - x^3$. By restricting the domain and codomain appropriately, obtain from $f$ a bijective function $g$. Sketch the graphs of $g$ and $g^{-1}$. Note that there are several choices for $g$.
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To do this, we can find its critical points by taking the first derivative and setting it to zero: f'(x) = 1 - 3x^2 Setting f'(x) = 0, we get: 1 - 3x^2 = 0 x^2 = 1/3 x = ±√(1/3) These are the critical points of the function. Now, we can analyze the second Show more…
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