00:01
Okay, so we're given the function f of x is equal to 8x, and we're given the value of a being negative 3.
00:12
Now, negative 3 for the a value just really means that that's the x coordinate of our point.
00:19
So, unfortunately, at this point, we don't know what our y value is, but if i substitute negative 3 into my original equation, i can find out that my x value would be negative 3, and since negative 3 times 8 is negative 24, the entire point that we're working with right now is this negative 3, negative 24.
00:41
Now, if i wanted to write the equation of the tangent line, the first thing i need to do is have a slope and a point.
00:47
Well, what's nice is we already have the point.
00:48
We just have to find the slope.
00:50
So the first thing that i want to do is find the derivative of my function, which will allow, which will give me the equation that will find the slope of the tangent line at any point.
01:00
Now, because this is technically 8x to the first, i would take 1 times 8, which is just 8, and then i'm going to have x to the 0, which is the 1 minus 1...