Let
∫₀² f(x) dx = -2, ∫₀³ f(x) dx = 13, ∫₀² g(x) dx = 11, ∫₂³ g(x) dx = 9,
Use these values to evaluate the given definite integrals.
a) ∫₀² (f(x) + g(x)) dx =
b) ∫₀³ (f(x) - g(x)) dx =
c) ∫₂³ (3f(x) + 2g(x)) dx =
d) Find the value a such that ∫₀³ (af(x) + g(x)) dx = 0.
a =