Question

Let \[ f(x)=2 x^{3}+6 x+4 \] Use the limit definition of the derivative to calculate the derivative of \( f \) : \[ f^{\prime}(x)=\square \text {. } \] Use the same formula from above to calculate the derivative of this new function (i.e. the second derivative of \( f \) ): \[ f^{\prime \prime}(x)= \] \( \square \)

          Let
\[
f(x)=2 x^{3}+6 x+4
\]

Use the limit definition of the derivative to calculate the derivative of \( f \) :
\[
f^{\prime}(x)=\square \text {. }
\]

Use the same formula from above to calculate the derivative of this new function (i.e. the second derivative of \( f \) ):
\[
f^{\prime \prime}(x)=
\]
\( \square \)

Let

f(x)=2 x^3+6 x+4

Use the limit definition of the derivative to calculate the derivative of f :

f^'(x)=□.

Use the same formula from above to calculate the derivative of this new function (i.e. the second derivative of f ):

f^''(x)=

□

Added by Melissa V.

Calculus for AP

Jon Rogawski & Ray Cannon 2nd Edition

Chapter 3

Instant Answer

Solved by Expert Mukesh Devi

Step 1

\[ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \] Show more…

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Let \[ f(x)=2 x^{3}+6 x+4 \] Use the limit definition of the derivative to calculate the derivative of \( f \) : \[ f^{\prime}(x)=\square \text {. } \] Use the same formula from above to calculate the derivative of this new function (i.e. the second derivative of \( f \) ): \[ f^{\prime \prime}(x)= \] \( \square \)