Question

Let $f(x) = \begin{cases} 5x - 5 & \text{if } x < 9 \\ c & \text{if } x = 9 \\ -2x + 3 & \text{if } x > 9 \end{cases}$ $\lim_{x \to 9^-} f(x) =$ $\lim_{x \to 9^+} f(x) =$ $f(9) =$ $f(x)$ cannot be made continuous because $\circ f(9)$ does not exist $\circ \lim_{x \to 9} f(x)$ does not exist $\circ$ Trick question! Any function can be made continuous

          Let $f(x) = \begin{cases} 5x - 5 & \text{if } x < 9 \\ c & \text{if } x = 9 \\ -2x + 3 & \text{if } x > 9 \end{cases}$
$\lim_{x \to 9^-} f(x) =$
$\lim_{x \to 9^+} f(x) =$
$f(9) =$
$f(x)$ cannot be made continuous because
$\circ f(9)$ does not exist
$\circ \lim_{x \to 9} f(x)$ does not exist
$\circ$ Trick question! Any function can be made continuous

Let f(x) = 5x - 5 if x < 9
c if x = 9
-2x + 3 if x > 9
limx → 9^- f(x) =
limx → 9^+ f(x) =
f(9) =
f(x) cannot be made continuous because
∘ f(9) does not exist
∘limx → 9 f(x) does not exist
∘ Trick question! Any function can be made continuous

Added by John S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sutara K

03/07/2022

Step 1

In this case, f(x) = 5x - 5 for x < 9. So, as x approaches 9 from the left, f(x) approaches 5(9) - 5 = 40. Show more…

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Thanks for your feedback!

Let f(x)={(5x-5 if x<9),(c if x=9),(-2x+3 if x>9):} lim_(x->9^(-))f(x)= lim_(x->9^(+))f(x)= f(9)= f(x) cannot be made continuous because f(9) does not exist lim_(x->9)f(x) does not exist Trick question! Any function can be made continuous 5x-5 6>x Letf=c ifx=9 -2x+3ifx>9 lim f -9 lim fx x-9+ f9= f() cannot be made continuous because O f(9) does not exist O lim f() does not exist -9 O Trick question! Any function can be made continuous Submit Question