Let f(x) and g(x) be differentiable functions such that f(3) = 2, f'(3) = 4, g(3) = 5, and g'(3) = 3 If h(x) = f(x) \cdot g(x), then find h'(3). Give the exact value. NO DECIMALS. h'(3) =
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The product rule states that if h(x) = f(x)g(x), then h'(x) = f'(x)g(x) + f(x)g'(x). So, applying the product rule, we have: h'(x) = f'(x)g(x) + f(x)g'(x) Now, let's substitute the given values into this equation: h'(3) = f'(3)g(3) + f(3)g'(3) We are given that Show more…
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