Let \( f(x)=x^{2} \sqrt{2 x+12} \), the equation of tangent line to the graph of \( f(x) \) at \( x=2 \ldots \) UEE
Added by Christopher C.
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Step 1
Substitute x=2 into the function f(x): f(2) = (2)^2 * sqrt(2*2+12) = 4 * sqrt(16) = 4 * 4 = 16 So, the point on the graph is (2,16). Show more…
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