6) Let $g(x) = \int_{x^2}^{x^3} \cos^2(y) dy$. Find $g''(x)$.
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g'(x) = d/dx [∫_(x^2)^(x^3) cos^2(y) dy] Using the Fundamental Theorem of Calculus, we can differentiate under the integral sign: g'(x) = cos^2(x^3) * (3x^2) - cos^2(x^2) * (2x) Show more…
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