00:01
Okay, so we have that h is the set of all vectors of the form minus 2t, t3t, for t in the real numbers.
00:09
So i've just written this in set notation.
00:13
So the next step is we can play a factor of t from all of these components.
00:17
So we have t times minus 2, 1, 3, t in r.
00:26
And this is exactly the span of this vector, because we have all multiples of this vector.
00:34
So this is exactly the span of the vector minus 2, 1, 3.
00:42
Okay, so let's look at our options.
00:46
So a, why does this show that this is a subspace? so part a, since the zero vector is not in the span, or this is false, the zero vector is in the span because we can just take t equals zero...