Question

Let $h(x) = f(x)g(x)$. If $f(x) = 4x^2 - 3x$ and $g(x) = \ln(3x - 1)$, what is $h'(x)$? Select the correct answer below. $h'(x) = (3 - 8x) \ln(3x - 1) + \frac{12x^2 - 9x}{1 - 3x}$ $h'(x) = (8x - 3)(3x - 1) + \frac{12x^2 - 9x}{3x - 1}$ $h'(x) = (8x - 3) \ln(3x - 1) + \frac{4x^2 - 3x}{3x - 1}$ $h'(x) = (8x - 3) \ln(3x - 1) + \frac{12x^2 - 9x}{3x - 1}$ $h'(x) = (8x - 3) \ln(3x - 1) - \frac{12x^2 - 9x}{3x - 1}$

Name: let hx fxgx if fx 4x2 3x and gx ln3x 1 what is hx select the correct answer below hx 3 8x ln3x 1 frac12x2 9x1 3x hx 8x 33x 1 frac12x2 9x3x 1 hx 8x 3 ln3x 1 frac4x2 3x3x 1 hx 8x 3 ln3x 1 frac 61632
Uploaded: 2022-04-27T11:01:42-08:00
Duration: 1 min 48 s
Channel: Suman Saurav Thakur
Description: let hx fxgx if fx 4x2 3x and gx ln3x 1 what is hx select the correct answer below hx 3 8x ln3x 1 frac12x2 9x1 3x hx 8x 33x 1 frac12x2 9x3x 1 hx 8x 3 ln3x 1 frac4x2 3x3x 1 hx 8x 3 ln3x 1 frac 61632

          Let $h(x) = f(x)g(x)$. If $f(x) = 4x^2 - 3x$ and $g(x) = \ln(3x - 1)$, what is $h'(x)$?
Select the correct answer below.
$h'(x) = (3 - 8x) \ln(3x - 1) + \frac{12x^2 - 9x}{1 - 3x}$
$h'(x) = (8x - 3)(3x - 1) + \frac{12x^2 - 9x}{3x - 1}$
$h'(x) = (8x - 3) \ln(3x - 1) + \frac{4x^2 - 3x}{3x - 1}$
$h'(x) = (8x - 3) \ln(3x - 1) + \frac{12x^2 - 9x}{3x - 1}$
$h'(x) = (8x - 3) \ln(3x - 1) - \frac{12x^2 - 9x}{3x - 1}$

$let hx fxgx if fx 4x2 3x and gx ln3x 1 what is hx select the correct answer below hx 3 8x ln3x 1 frac12x2 9x1 3x hx 8x 33x 1 frac12x2 9x3x 1 hx 8x 3 ln3x 1 frac4x2 3x3x 1 hx 8x 3 ln3x 1 frac 61632$

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