Question

Let $h(x) = \int_{2}^{-8/x} \arctan(t)dt$. Use the Fundamental Theorem of Calculus to find $h'(x)$.\n$h'(x) = $

Name: Let h(x) = ∫2^-8/xarctan(t)dt. Use the Fundamental Theorem of Calculus to find h'(x).h'(x) =
Uploaded: 2023-08-21T16:53:08-08:00
Duration: 1 min 26 s
Channel: Sri K
Description: Let h(x) = ∫2^-8/xarctan(t)dt. Use the Fundamental Theorem of Calculus to find h'(x).h'(x) =

          Let $h(x) = \int_{2}^{-8/x} \arctan(t)dt$. Use the Fundamental Theorem of Calculus to find $h'(x)$.\n$h'(x) = $

Added by Karen B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

08/21/2023

Step 1

h'(x) = d/dx [∫2^(-(8/x)) arctan(t) dt] Show more…

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Let h(x)=int_2^(-(8)/(x)) arctan(t)dt. Use the Fundamental Theorem of Calculus to find h^(')(x) h^(')(x)= Leth() arctan(t)dt. Use the Fundamental Theorem of Calculus to find h'(). h'()= preview answers