Since the zero polynomial is not in \(H\) (as \(1 \neq 0\)), \(H\) does not contain the zero vector required for it to be a subspace. Therefore, \(H\) is not a subspace of \(P3\).
**Step 2:**
For part (b) where \(H = \{p(t) \mid p(3) = 0\}\), we need to
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