00:01
Okay, so we are going to prove the claim in our exercise by induction.
00:07
So induction.
00:11
Okay, well, we are going to proceed by induction on the degree of our polynomial p of z.
00:19
Now, if the degree of our polynomial p of z is equal to one, then this thing implies what? this thing implies that p of z is a linear polynomial so in particular this thing shows that p of z is going to be of the form a z plus b with a different from zero now how can we write a z plus b well this is actually pretty easy we can write z as okay we can write z as z as z minus z 0 plus z zero so p of z is going to be equal to what well this guy is going to be equal to a multiplied by z minus z plus okay so here we're going to have plus a multiplied by z 0 plus b perfect so our claim is true so claim through for degree of p of z equals 1 perfect now let's show that our claim true for n minus 1 implies our claim true true for n so claim true for n.
02:09
Okay, perfect.
02:11
Now we have a polynomial p of z of degree n.
02:17
Now this one is a complex polynomial, that is a polynomial with complex coefficients.
02:23
So in particular, we can find z star, which is going to be a root of p of z.
02:38
Because we know that every polynomial with complex coefficients has at least a root.
02:45
Actually, we can always factorize this polynomial as a product of linear polynomials because we are working on the field of complex numbers.
02:56
Perfect.
02:57
That being said, p of z can be written as what? it can be written as q of z multiplied by z minus z star.
03:08
Where the degree of our polynomial q is n minus 1.
03:14
Perfect...