Let \(R\) be the region bounded by the curves \(y^2 = 2x\) and \(x = 3y\). What is the volume of the solid generated by rotating \(R\) about the \(y\)-axis?
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To find the points of intersection, we can substitute x = 3y into the first equation: y^2 = 2(3y) y^2 = 6y y^2 - 6y = 0 y(y - 6) = 0 y = 0 or y = 6 So the points of intersection are (0,0) and (6,18). Show more…
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