00:01
In this question, to show that tn is equal to on based on the given recurrence relation, we can use the master's theorem, which is a common method for analyzing the time complexity of recursive algorithms.
00:11
So, the master's theorem applies to recurrence relation in the form of tn is equal to atn divided by b plus fn.
00:19
So, tn is the time complexity, a is the number of subproblem, n divided by b is the size of each subproblem, and fn is the time spent on the dividing the problem and combining the subproblem solution.
00:31
So, let's first write the recurrence the way that allows the applies apply the master's theorem.
00:36
So, tn is equal to tn divided by 5 plus t multiplied by 7n divided by 10 plus 6 plus on.
00:44
So, t dash n is equal to t multiplied by n divided by 5 plus t multiplied by 7n divided by 10 plus 6.
00:56
So, here a is equal to 2, 2 recursive calls, b is equal to 5, size of reduction factor for the first call and c is equal to 7 divided by 10.
01:05
So, size reduction factor for the second call and fn is equal to o1.
01:10
So, we can apply here the theorem...