00:01
Hi there, so for this problem, we are told to denote the volume of a cylinder as capital b.
00:08
So we know that the volume of a cylinder is pi times its radius square times the height.
00:15
So with that said, for part a of this problem, we are asked about how are the differential in the volume, the differential in the height, and the differential in the radius related.
00:27
So what we are going to do is to take the volume that we are given, and thereby both sides with respect to time.
00:35
So for the left side, we obtain just simply the derivative of the volume with respect to time.
00:40
And for the right side, taking out the constant, which is pi, we have the derivative of the product between the radius and the height.
00:48
So we can apply in here the derivative of a product.
00:54
So that will be pi.
00:55
And the first derivative is two times the radius times the high, times the rate of change of the radius could respect the time.
01:09
This plus the radius square times the rate of change of the high could respect the time.
01:18
So that is the relationship between the differentials.
01:22
That's a solution for part a of this problem...