00:01
Hello students, to find the matrix of the orthogonal projection under the subspace w, we need to first find an orthonormal basis for w.
00:09
So, we can use the gram -schmidt process to find the orthonormal basis u1, u2 for w.
00:16
So, u1 equal to minus 2, 1, 1, 1 by square root 6.
00:25
U2 equal to 1 by square root 62 minus 6, 5, 1 minus 6, 5, 1, 1 by root 62 into 1 by root 6 minus 2, 1, 1 is equal to minus 6, 5, 1, 1 by root 62 minus 10 by 62 minus 2, 1, 1, 2, 1, 1 square root 6 into square root 6.
01:21
Simplifying this will have minus 12 by 31, 7 by 31, 11 by 31...