Let X be a discrete random variable such that P(X = 0) = p, P(X = 1) = 2p, P(X = 2) = 3p, P(X = 4) = 4p. a) Find the expected value of X b) Find the variance of X
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Since the probabilities of all possible outcomes must sum up to 1, we have: P(X = 0) + P(X = 1) + P(X = 2) + P(X = 4) = 1 P + 2p + 3p + 4p = 1 10p = 1 p = \frac{1}{10} Now we can find the expected value of X, which is given by: E(X) = \sum_{i} x_i P(X = Show more…
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